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DS - Set 25 Math

Expert replies
by f2001290 » Tue Jun 12, 2007 1:43 pm
If the average (arithmetic mean) of the assessed values
of x houses is $212,000 and the average of the assessed
values of y other houses is $194,000, what is the average
of the assessed values of the x+y houses?
(1) x+y=36
(2) x=2y

I chose B, but surprisingly it turned out to be C. Clueless:)
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Source: — Data Sufficiency |

by mschling52 » Thu Jun 14, 2007 9:04 am
I agree with you...I think it's B
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by simplythebest » Thu Jun 14, 2007 10:36 pm
I think the answer should be C.

WE need

($212,000*x + $194,000y) / x + y

and only with both the statements we can exactly find the assessed values of X+Y
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by mschling52 » Fri Jun 15, 2007 4:46 am
You are right, that is the formula we need to solve, but if we know just (2) then that formula becomes

(212,000(2y) + 194,000y)/((2y)+y)

= (618,000y)/(3y) = 206,000
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by simplythebest » Fri Jun 15, 2007 5:25 am
Grr..Silly mistake...yup...It should be B...think i should write "Read questions carefully" a 1000 times imposition..

Thanks Mate !!!
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