If y is >= 0, what is the value of x?
1) Modulus (x-3) >= y
2) Modulus (x-3) <= -y
Answer is apparently B. How come?
1) Modulus (x-3) >= y
2) Modulus (x-3) <= -y
Answer is apparently B. How come?
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how do you know on this inequality to plug #s instead of trying to get fancy and manipulate the equalities? i.e. test positive/negative case?puneetdua wrote:Ans shd be B - Coz
1) |x-3| >=y
IF y =2 then x can be 5 or 6
Not sufficient
2) |x-3| <= -y
we are already given y>=0
IF we take y >= 1 then the condition given in 2) doesnt hold true
e.g. -> y = 1
|x-3| <= -1 -----> cant be coz of modulus
So we need to take y = 0
and if we take y=0 then there is a ceratin value of x
hence B
Good question indeed...!!
how do you know on this inequality to plug #s instead of trying to get fancy and manipulate the equalities? i.e. test positive/negative case?puneetdua wrote:Ans shd be B - Coz
1) |x-3| >=y
IF y =2 then x can be 5 or 6
Not sufficient
2) |x-3| <= -y
we are already given y>=0
IF we take y >= 1 then the condition given in 2) doesnt hold true
e.g. -> y = 1
|x-3| <= -1 -----> cant be coz of modulus
So we need to take y = 0
and if we take y=0 then there is a ceratin value of x
hence B
Good question indeed...!!
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