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Senior | Next Rank: 100 Posts
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by ukr.net » Fri Dec 14, 2007 10:02 am
x<0 than square root of(-x|x|) is

-x
-1
1
x
square root of x
Last edited by ukr.net on Fri Dec 14, 2007 12:30 pm, edited 1 time in total.
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Source: — Data Sufficiency |
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by TSonam » Fri Dec 14, 2007 10:27 am
can you post your questions properly? cant understand your question.
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ds

by ukr.net » Fri Dec 14, 2007 12:31 pm
I've reposted the question
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by sujaysolanki » Fri Dec 14, 2007 11:33 pm
Given that x < 0 the sqrt of -x^2 will be x as sqrt will be positive always.

Hence x
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ds

by ukr.net » Sun Dec 16, 2007 5:17 am
The answer should be -x ???
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by austindude » Sun Dec 16, 2007 11:16 am
The answer should be -x, as
1. x<0
2. if it is not -x the sq root would not be possible of a negative number

Thanks,
AustinDude.
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Re: DS GMATPrep

by gabriel » Sun Dec 16, 2007 12:03 pm
ukr.net wrote:x<0 than square root of(-x|x|) is

-x
-1
1
x
square root of x
Well this question has been done to death on the forum, but here we go anyway ..

Let X = -2 , so we need the sqroot of (-(-2)mod(-2)) = (2*2) = 4, Now the sqroot of a number is always positive so sqroot of 4 = 2

So we have sqroot(-(-2)mod(-2)) = 2, We know X= -2, so 2 = -X, hence the answer is -X..

Regards
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