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by vinviper1 » Mon Jun 09, 2008 7:10 pm
bumpy-bump. Thanks
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by Stuart@KaplanGMAT » Tue Jun 10, 2008 1:07 pm
From the original: we know that M + Tu + W + Th + F + Sa + Su = 90

We know that Sa is the biggest and Fr is the 2nd biggest.

We know that each day is a different integer.

Q: is F > 11?

(1) Th = 8

Well, that means the rest of the days add up to 82. If we pick:

M = 1, Tu = 2, W = 3, Su = 4, F=5 and Sa = the rest, then we get a "no" answer to the question. However, if we pick:

M = 1, Tu = 2, W = 3, Su = 4, F=12 and Sa = the rest, then we get a "yes" answer to the question.

Could be "no" or "yes", therefore insufficient.

(2) Sa = 38

Let's try to make F NOT greater than 11. If we let F=11, then the maximum that the other 5 terms could be is 10, 9, 8, 7 and 6. However, 6 + 7 + 8 + 9 + 10 + 11 + 38 = 89. So, to get our total of 90, F must be at least 12 (and is therefore definitely > 11).

(2) is sufficient and (1) isn't: choose (B).
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