Solution:
Now 96 is the product of 3 single digit numbers.
96 = 12 * 8 = 3*4*8 = 2*6*8 =4*4*6.
So the units digit, tens digit and hundreds digit can be either 3, 4 and 8 or 2, 6 or 8 or 4, 4, 6 in any order.
Consider first statement (1) alone.
m is odd.
So the units digit of m is odd.
Only possibility is 3 from the combination of 3, 4 and 8.
So (1) alone is sufficient.

Next consider (2) alone.
The hundreds digit is 8.
So any of the 2 combinations 3, 4, 8 or 2, 6, 8 are possible.
So if hundreds digit is 8, units and tens digit can be any of 2, 3, 4 or 6.
Since we do not get a unique answer, (2) alone is not sufficient.

The correct answer is (A).

One more for C...

(i) can give you two numbers 483 or 843..... insuff

as explained by Rahul, (ii) is INSuff...

(i) & (ii) gives a unique number - 843

Hence C.... correct me if i am wrong

They want the units digit and not the number. Both in 483 and in 843, units digit is 3.