Solution:
Now 96 is the product of 3 single digit numbers.
96 = 12 * 8 = 3*4*8 = 2*6*8 =4*4*6.
So the units digit, tens digit and hundreds digit can be either 3, 4 and 8 or 2, 6 or 8 or 4, 4, 6 in any order.
Consider first statement (1) alone.
m is odd.
So the units digit of m is odd.
Only possibility is 3 from the combination of 3, 4 and 8.
So (1) alone is sufficient.
Next consider (2) alone.
The hundreds digit is 8.
So any of the 2 combinations 3, 4, 8 or 2, 6, 8 are possible.
So if hundreds digit is 8, units and tens digit can be any of 2, 3, 4 or 6.
Since we do not get a unique answer, (2) alone is not sufficient.
The correct answer is (A).
Rahul Lakhani
Quant Expert
Gurome, Inc.
https://www.GuroMe.com
On MBA sabbatical (at ISB) for 2011-12 - will stay active as time permits
1-800-566-4043 (USA)
+91-99201 32411 (India)