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double tennis

Expert replies
by ketkoag » Sat Jun 20, 2009 1:40 am
A group of 8 friends want to play double tennis. How many different ways can the group be divided into 4 teams of two people?

OA:105
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Source: — Problem Solving |

by rahulg83 » Sat Jun 20, 2009 3:31 am
I am confused here :cry:
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by rah_pandey » Sat Jun 20, 2009 5:36 am
Ketkoag,
Are you sure about the answer?
according to me it should be
8c2+6c2+4c2+2c2=49 ways

can anybody throw some light
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by ketkoag » Sun Jun 21, 2009 2:21 am
about the OA, 105 is what is mentioned here..
Interestingly, they have mentioned a formula in the OE i.e.
the number of ways of dividing "mn" things into "m" groups of "n" each :
(mn)!/(m!) * (n!)^m

I don't get this formula either.. please help me understand this formula and its application..
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by rahulg83 » Sun Jun 21, 2009 2:31 am
https://www.beatthegmat.com/friends-want ... 18991.html

Check Ian's post here...nice explanation...Googled it :)
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by ketkoag » Mon Jun 22, 2009 3:06 am
yeah, Ian has explained it very well. thanks..
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