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Expert replies
by bacali » Tue Nov 25, 2008 8:14 am
Of the families in City X in 1994, 40 percent owned a personal computer. The number of families in City X owning a computer in 1998 was 30 percent greater than it was in 1994, and the total number of families in City X was 4 percent greater in 1998 than it was in 1994. What percent of the families in City X owned a personal computer in 1998?


A. 50%
B. 52%
C. 56%
D. 70%
E. 74%


OA: A
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Source: — Problem Solving |

by mals24 » Tue Nov 25, 2008 8:23 am
One of the simplest ways to solve questions like these is to pick numbers.

Let the total families in 1994 = 100
Number of families owned PC = 40%*100 = 40

In 1998

Number of families that own PC increased by 30% = 40 + 30%40 = 52
Number of families increased by 4% = 104

Hence percent of the families in City X owned a personal computer in 1998

52/104 = 1/2 = 50%
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