Nandish,
A square can be called a special rectangle having equal length and breadth.
This question can be solved logically.
We know that the area of a rectangle = Length (a) * Breadth (b) = a*b
Clearly, statement 1 is insufficient as the area of the square = a^2. We cannot compare a^2 and a*b as we have no information about b.
Similarly, statement 2 is insufficient as we do not have any information about the other side of the rectangle: it may be equal to, greater than or smaller than that of the square, resulting in all possible results: Area is equal, more, and less.
However, combining both the statements will result in a unique answer.
Area of square = a^2;
Area of rectangle = a*(2a) =
2a^2 > a^2.
The answer is a unique 'NO'. OA
C
Hope this helps!
--Jay
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