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Does r,s lie on the line

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Source: — Data Sufficiency |
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Two variables unless you combine the 2 statements

by jcan-gmatter » Tue Nov 13, 2007 11:28 am
Stat 1). You have 2 unknowns which you cannot solve for
(3r + 2 -s) (4r + 9 - s ) = 0
=> 3r + 2 - s = 0 : Two variables. Cannot solve for either one
=> 4r + 9 - s = 0 : Two variables. Cannot solve for either one

Stat 2) Same. You have 2 unknowns which you cannot solve for
(4r - 6 - s) (3r + 2 - s ) = 0
=> 4r - 6 - s = 0 : Two variables. Cannot solve for either one
=> 3r + 2 - s = 0 : Two variables. Cannot solve for either one

Combined
You can eliminate one of the variables ( r or s ) and find the answer to see if it contains the point.
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Re: Two variables unless you combine the 2 statements

by gmatrant » Tue Nov 13, 2007 5:31 pm
jcan-gmatter wrote:Stat 1). You have 2 unknowns which you cannot solve for
(3r + 2 -s) (4r + 9 - s ) = 0
=> 3r + 2 - s = 0 : Two variables. Cannot solve for either one
=> 4r + 9 - s = 0 : Two variables. Cannot solve for either one

Stat 2) Same. You have 2 unknowns which you cannot solve for
(4r - 6 - s) (3r + 2 - s ) = 0
=> 4r - 6 - s = 0 : Two variables. Cannot solve for either one
=> 3r + 2 - s = 0 : Two variables. Cannot solve for either one

Combined
You can eliminate one of the variables ( r or s ) and find the answer to see if it contains the point.
Hmm...
In the first case I have two equations
3r + 2 - s = 0
4r + 9 - s = 0
Can I solve for r ans s.

Similarly for case 2.
So shouldnt answer be D.
your comments.
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Re: Two variables unless you combine the 2 statements

by gmatrant » Wed Nov 14, 2007 8:27 pm
where have I gone wrong..
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Re: Two variables unless you combine the 2 statements

by gabriel » Wed Nov 14, 2007 10:53 pm
gmatrant wrote:
jcan-gmatter wrote:Stat 1). You have 2 unknowns which you cannot solve for
(3r + 2 -s) (4r + 9 - s ) = 0
=> 3r + 2 - s = 0 : Two variables. Cannot solve for either one
=> 4r + 9 - s = 0 : Two variables. Cannot solve for either one

Stat 2) Same. You have 2 unknowns which you cannot solve for
(4r - 6 - s) (3r + 2 - s ) = 0
=> 4r - 6 - s = 0 : Two variables. Cannot solve for either one
=> 3r + 2 - s = 0 : Two variables. Cannot solve for either one

Combined
You can eliminate one of the variables ( r or s ) and find the answer to see if it contains the point.
Hmm...
In the first case I have two equations
3r + 2 - s = 0
4r + 9 - s = 0
Can I solve for r ans s.

Similarly for case 2.
So shouldnt answer be D.
your comments.
You cannot solve 3r + 2 - s = 0, 4r + 9 - s = 0 simultaneously to get a value for r and s .... Remember to solve two linear equations simultaneously the variables need to satisfy both the equation eg. 2x+3y=5 and 3x+2y=5 over here both the equations are true

Whereas in the above equation we say 3r+2-s = 0 or 4r+9-s = 0 that is both of them are not true..that is only one of them is equal to 0 ..

Regards.
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by swle24 » Thu Nov 15, 2007 2:47 am
if y=3x+2 contains (r,s) that means s=3r+2
1. (3r+2-s)*(4r+9-s)=0 then 3r+2-s=0 or 4r+9-s=0 insuff.
2. (4r-6-s)*(3r+2-s)=0 then 4r-6-s=0 or 3r+2-s=0 insuff
but combined 1+2 we get that 3r+2-s=0 so 3r+2=s sufficient
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by lawalx » Tue Nov 27, 2007 1:41 am
i think the answer should be D cos combining both i gt the same answers as workin for each of the them.

what am i doin wrong?
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by sujaysolanki » Tue Nov 27, 2007 1:55 am
lawalx ..i will try to be put it in a simple way and as gabriel has put it earlier ..let me know if it makes sense

Let (3r + 2 -s) = a and (4r + 9 - s ) = b (4r - 6 - s) = c

From 1

a * b = 0 so this means either a is 0 or b is 0 ..but we cant say which one

From 2

c * a = 0 so this means either a is 0 or b is 0 ..but we cant say which one


Combining a = 0 ..which gives the same equation as the stem

Hope this helps
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