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Does \(4^a = 4^{-a} + b?\)
(1) \(16^a = 1 + \dfrac{2^{2a}}{b^{-1}}\)
(2) \(a = 2\)
Answer: A
Source: Manhattan GMAT
(1) \(16^a = 1 + \dfrac{2^{2a}}{b^{-1}}\)
(2) \(a = 2\)
Answer: A
Source: Manhattan GMAT
