i read in this forum itself that
'a' raise to the power 'm' raise to the power 'n' = a raise to the power ( m raise to the power n)
'a' raise to the power 'm' raise to the power 'n' NE (a raise to the power m) raise to the power n
if this be the case then is the solution mentioned in the 300+ question wrong.
Ques: What is the units digit of a^36?
a) a^2 has 9 as the units digit
b) a^3 has 3 as the units digit
Solution:
1) a^2 ends in 9
Well, a^36 = (a^2)^18
If we know that a^2 ends in 9, it's certainly possible to calculate the units digit of (...9)^18 - sufficient.
2) a^3 ends in 3
Well, a^36 = (a^3)^12
If we know that a^3 ends in 3, it's certainly possible to calculate the units digit of (...3)^12 - sufficient.
Each statement is sufficient alone: choose D.
Please clarify whether a raise to power 36 = (a raise to the power 2) raise to the power 18 or is 'a' raise to power 36 = (a raise to the power ( 2 raise to the power 18) ... I understand that the logic says the former to be correct and the latter downright improbable but please clarify the formula mentioned above with regard to this problem.
Regards,
Waltz2Salsa[/img]
'a' raise to the power 'm' raise to the power 'n' = a raise to the power ( m raise to the power n)
'a' raise to the power 'm' raise to the power 'n' NE (a raise to the power m) raise to the power n
if this be the case then is the solution mentioned in the 300+ question wrong.
Ques: What is the units digit of a^36?
a) a^2 has 9 as the units digit
b) a^3 has 3 as the units digit
Solution:
1) a^2 ends in 9
Well, a^36 = (a^2)^18
If we know that a^2 ends in 9, it's certainly possible to calculate the units digit of (...9)^18 - sufficient.
2) a^3 ends in 3
Well, a^36 = (a^3)^12
If we know that a^3 ends in 3, it's certainly possible to calculate the units digit of (...3)^12 - sufficient.
Each statement is sufficient alone: choose D.
Please clarify whether a raise to power 36 = (a raise to the power 2) raise to the power 18 or is 'a' raise to power 36 = (a raise to the power ( 2 raise to the power 18) ... I understand that the logic says the former to be correct and the latter downright improbable but please clarify the formula mentioned above with regard to this problem.
Regards,
Waltz2Salsa[/img]
