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by sanju09 » Thu Sep 15, 2011 4:00 am
A band wants to distribute its music on compact discs (CD’s). The equipment to produce the CD’s costs $250, and blank CD’s cost $5.90 for a package of 10. Which of the following represents the total cost, in dollars, to produce n CD’s, where n is a multiple of 10?
(A) (250 + 0.59) n
(B) 250 + 0.59 n
(C) (250 + 5.90) n
(D) 250 + 5.90 n
(E) 250 n + 5.90



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by cans » Thu Sep 15, 2011 4:14 am
equipment: 250
10 CD: 5.9
thus 1 cd: .59
for n cd, .59n
cost = 250 + .59n
IMO B
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by sanju09 » Thu Sep 15, 2011 4:21 am
cans wrote:equipment: 250
10 CD: 5.9
thus 1 cd: .59
for n cd, .59n
cost = 250 + .59n
IMO B
Please remember here that n is a multiple of 10.
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by shankar.ashwin » Thu Sep 15, 2011 4:28 am
N is a multiple on 10.

B.

To verify, minimum possibility is 1 pack (n=10) Only B satisfies
Last edited by shankar.ashwin on Thu Sep 15, 2011 4:51 am, edited 1 time in total.
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by cans » Thu Sep 15, 2011 4:33 am
yeah i know n is multiple of 10. for 10, we have 5.9, for n we will have (5.9)(n/10) = 0.59n
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by sanju09 » Thu Sep 15, 2011 4:50 am
cans wrote:yeah i know n is multiple of 10. for 10, we have 5.9, for n we will have (5.9)(n/10) = 0.59n
good point! OA is [spoiler]B[/spoiler]
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