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Distinct points A, B, C, D

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by s_raizada » Thu May 29, 2008 1:39 pm
Distinct points A, B, C, D form a right triangle ABC with a height BD. What is the value of AB times BC ?

1) AB = 6

2) The product of the non-hypotenuse sides is equal to 24
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by netigen » Thu May 29, 2008 6:02 pm
If BD is the height then it means AC = hypotenuse

hence AB and BC are non hypotenuse sides

so B is sufficient.
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by chidcguy » Thu May 29, 2008 6:50 pm
The tricky part of this Q is to draw the right triangle in such a way that AC is the base and BD is the height. if we draw a right triangle as we draw most of the times, we can't fit in BD. I lost time there debating whether the Q is correct.

B is sufficient for the reason netigen explained.
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by s_raizada » Sat May 31, 2008 5:02 am
netigen,
I don't understand the logic if BD is height then AC is hypotenous.

How did you conclude that?
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by chidcguy » Sat May 31, 2008 8:06 am
As I said, you have to draw a normal triangle and B happens to be the top vertex and AC is the base. Then Angle B=90 degree and AC is the side opposite to it and hence AC is hypotenuse.
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by netigen » Sat May 31, 2008 11:01 am
s_raizada wrote:netigen,
I don't understand the logic if BD is height then AC is hypotenous.

How did you conclude that?
It's a right angle triangle hence two sides are already heights in themselves. Question says that BD is a height but it is not a side of the triangle hence it should be the height on the hypotenuse.
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by s_raizada » Sun Jun 01, 2008 3:54 am
Thanks for clarifying this guys!

The whole time I kept thinking becaue ABC is right triange so one of the side of the triange ABC should be height, how can BD can be height.

Chiducguy, you rightly said the best way to sort this kind of problems is to draw them.
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