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Start the planA.)180-x/2
B.)x + 60/4
C.)300-x/5
D.)600/115-x
E.)12,000/x+200
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right wrong
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Start the planHere's an algebraic approach.During a trip, Francine traveled x percent of the total distance at an average speed of 40 miles per hour and the rest of the distance at an average speed of 60 miles per hour. In terms of x, what was Francine's average speed for the entire trip?
A. (180-x)/2
B. (x+60)/4
C. (300-x)/5
D. 600/(115-x)
E. 12,000/(x+200)
Since average speed = (total distance)/(total time), we have (note: in the parenthesis is what we do to the numerator and denominator to obtain the next line)datonman wrote:During a trip, Francine traveled 'x' percent of the total distance at an average speed of 40 miles per hour and the rest of the distance at an average speed of 60 miles per hour. In terms of 'x', what was Francine's average speed for the entire trip?
A.)180-x/2
B.)x + 60/4
C.)300-x/5
D.)600/115-x
E.)12,000/x+200
