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by gmattester » Fri Aug 22, 2008 11:21 am
The figure above shows the number of meters in the lengths of the four sides of a jogging path. What is the total distance around the path? [See Attachement]
(1) One of the sides of the path is 120 meters long.
(2) One of the sides of the path is twice as long as each of the two shortest sides.
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by anju » Fri Aug 22, 2008 11:35 am
is it 420 mt?
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by s_kaks » Fri Aug 22, 2008 12:24 pm
Yes.. the Ans seems to be 420 m
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by gmattester » Fri Aug 22, 2008 1:14 pm
I am sorry, this is DS question, not PS.
By mistake I posted here.
BTW which one is sufficient to answer this question
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by anju » Fri Aug 22, 2008 1:21 pm
gmattester wrote:I am sorry, this is DS question, not PS.
By mistake I posted here.
BTW which one is sufficient to answer this question
I guessed so.
B - stmt 2 is sufficient since 2x = x+60; 2x cannot be equal to 3x, the only side remaining is x+60
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by parallel_chase » Fri Aug 22, 2008 2:25 pm
I think the answer should be B.

Statement I

120 can be any of the three sides. Therefore Insufficient.

Statement II

one side is twice the other two shorter sides.

3x = 2x
or
x+60 = 2x

3x cannot be equal to 2x for any positive integer. Therefore x+60 =2x

x=60

Sufficient.

Hence B.
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by gmattester » Fri Aug 22, 2008 2:49 pm
parallel_chase wrote:I think the answer should be B.

Statement I

120 can be any of the three sides. Therefore Insufficient.

Statement II

one side is twice the other two shorter sides.

3x = 2x
or
x+60 = 2x

3x cannot be equal to 2x for any positive integer. Therefore x+60 =2x

x=60

Sufficient.

Hence B.
Great.......
Thanks for explanation.
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