Hi SaraLotfy,
The set (x,x,y,y,y,y) has 6 terms, so the median = y and the mean = (2x + 4y)/6
Since we're given that the set is "ascending", that means that y > x
The mean of those 6 terms MUST be less than y because those 2 x values (which are both less than y) would bring the average down.
As an example:
x = 1
y = 2
Set = 1,1,2,2,2,2
Median = 2
Average = 10/6 = 1.33333
Final Answer: The MEDIAN is greater than the mean
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Sara, it's a direct conceptual Question.
We have TWO "x" and FOUR "y". So, the count of "y" is more than "x".. So the MEAN would always be more nearer to "y" than to "x". But NOT be equal to "y"
So Mean = less than "y"
Median = "y"
Hence, [spoiler]Median > Mean[/spoiler]
We have TWO "x" and FOUR "y". So, the count of "y" is more than "x".. So the MEAN would always be more nearer to "y" than to "x". But NOT be equal to "y"
So Mean = less than "y"
Median = "y"
Hence, [spoiler]Median > Mean[/spoiler]
R A H U L
