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by SaraLotfy » Thu Sep 19, 2013 10:59 am
Given the ascending set {x,x,y,y,y,y}, what is greater, the median or the mean?
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by [email protected] » Thu Sep 19, 2013 12:21 pm
Hi SaraLotfy,

The set (x,x,y,y,y,y) has 6 terms, so the median = y and the mean = (2x + 4y)/6

Since we're given that the set is "ascending", that means that y > x

The mean of those 6 terms MUST be less than y because those 2 x values (which are both less than y) would bring the average down.

As an example:
x = 1
y = 2
Set = 1,1,2,2,2,2
Median = 2
Average = 10/6 = 1.33333

Final Answer: The MEDIAN is greater than the mean

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by theCodeToGMAT » Thu Sep 19, 2013 9:21 pm
Sara, it's a direct conceptual Question.

We have TWO "x" and FOUR "y". So, the count of "y" is more than "x".. So the MEAN would always be more nearer to "y" than to "x". But NOT be equal to "y"

So Mean = less than "y"
Median = "y"
Hence, [spoiler]Median > Mean[/spoiler]
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