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I am missing something here. The tens digit of 69 (6+1=7), but the tens digit of 78 (7+1 =8, not 7). Can you explain further?Rahul@gurome wrote:(1) The hundreds digit of 10n is 6 means 10n = 6(tens place)(units place); tens place can take the digits from 0 to 9 but units place has to be the digit 0 as n is a positive integer.
So, n = 6(tens place)
We can see that the tens digit of n will always be 6.
[If not clear take an example: Let 10n = 620, then n = 62. If we take 10n = 602 then n cannot be an integer as n = 602/10 = 60.2]
So, (1) is SUFFICIENT.
(2) The tens digit of n+1 is 7 so N can be 69 to 78, so tenth place of n is either 6 or 7. Since we don't have a unique answer, so (2) is NOT SUFFICIENT.
The correct answer is [spoiler](A)[/spoiler].
greenwich wrote:If n is a positive integer, what is the tens digit of n?
(1) The hundreds digit of 10n is 6.
(2) The tens digit of n+1 is 7.
Please provide explanations.
If we take n = 69, then 10n = 10(69) = 690; here hundreds digit of 10n is 6 and tens digit of n = 6.greenwich wrote: I am missing something here. The tens digit of 69 (6+1=7), but the tens digit of 78 (7+1 =8, not 7). Can you explain further?
You are treating n as a digit here, big silent mistakegreenwich wrote:I am missing something here. The tens digit of 69 (6+1=7), but the tens digit of 78 (7+1 =8, not 7). Can you explain further?
We switch to (2) with no hang-overs of (1)Rahul@gurome wrote:If we take n = 69, then 10n = 10(69) = 690; here hundreds digit of 10n is 6 and tens digit of n = 6.greenwich wrote: I am missing something here. The tens digit of 69 (6+1=7), but the tens digit of 78 (7+1 =8, not 7). Can you explain further?
But if we take n = 78, then 10n = 10(78) = 780; this is not possible as hundreds digit of 10n is not 6, it's 7 here, but according to statement (1), hundreds digit of 10n is 6.
Does that help?
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