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Digits Interchanged

Expert replies
by harsh.champ » Wed Feb 17, 2010 4:25 am
A number has 2 digits whose sum is 9.If 27 is added to the number,its digits get interchanged.How many prime divisors of that number are there ?

(A)1
(B)2
(C)3
(D)4
(E)5
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Source: — Problem Solving |

by money9111 » Wed Feb 17, 2010 8:49 am
i'm going to say A.

I made a table for the digits...

10's digit = X
1's digit = y

XY

X+Y=9


1 + 8 = 9 number would be 18 -> + 27 = 45 does not switch original numbers
2 + 7 = 9 number would be 27 -> + 27 = 54 does not switch original numbers
3 + 6 = 9 number would be 36 -> + 27 = 63 DING DING switches original numbers
4 + 5 = 9 number would be 45
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by ajith » Wed Feb 17, 2010 8:55 am
harsh.champ wrote:A number has 2 digits whose sum is 9.If 27 is added to the number,its digits get interchanged.How many prime divisors of that number are there ?

(A)1
(B)2
(C)3
(D)4
(E)5
let 'ab' be the number

a+b=9
10a+b +27 = 10b+a
b-a =3

b=6
a= 3
36 = 2^2*3^2 there are 2 prime divisors
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by shashank.ism » Wed Feb 17, 2010 8:55 am
harsh.champ wrote:A number has 2 digits whose sum is 9.If 27 is added to the number,its digits get interchanged.How many prime divisors of that number are there ?

(A)1
(B)2
(C)3
(D)4
(E)5
Let the number be XY
X+Y=9---(i)
10X+Y+27=10Y+X --> 9X+27 = 9Y --> Y-X=3 ---(ii)
Adding we get 2Y= 12 Y=6
X=3
so the no,. is 36 = 2x2x3x3 so no. of prime divisors = 2Ans B
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by money9111 » Wed Feb 17, 2010 9:01 am
i like your answers better
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by shashank.ism » Wed Feb 17, 2010 9:09 am
money9111 wrote:i like your answers better
Thanks money1119. i think there are times when you solve problem in general way rather than plugin and eliminationand you u reach to the answer much faster ....
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by money9111 » Wed Feb 17, 2010 9:11 am
yeah the way you guys did it is much more concise... i've done it like that before, but in this case it slipped my mind
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by shashank.ism » Wed Feb 17, 2010 9:14 am
money9111 wrote:yeah the way you guys did it is much more concise... i've done it like that before, but in this case it slipped my mind
I think similar questions have been posted in this forum now and then and I have posted the solution in the general way.. i hope you have gone thru those answers.
Well don't use plug in method for this question next time . You will certainly loose some of yor precious seconds...
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by money9111 » Wed Feb 17, 2010 9:16 am
i think the real issue here isn't the approach I took, but the fact that I got the same numerical answer and didn't put 2 and 2 together to realize that there are 2 prime divisors!!! lol
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by shashank.ism » Wed Feb 17, 2010 9:19 am
money9111 wrote:i think the real issue here isn't the approach I took, but the fact that I got the same numerical answer and didn't put 2 and 2 together to realize that there are 2 prime divisors!!! lol
yeah u were surely wrong at that point .. Be careful on the D day...
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by money9111 » Wed Feb 17, 2010 9:21 am
i'll be sure to be careful! thanks for the tip
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by harsh.champ » Wed Feb 17, 2010 11:26 pm
Hey Guys,
It is better to go by the formal approach rather than by plugging no.s as it takes approx. the same time.
Now,Let no. be 10x + y[xy].Now ,after adding 27 the digits are reversed.10y + x[yx]
So,we get the equation:-10x + y + 27 = 10y + x
=>9(x-y) + 27 = 0
=>x-y + 3 =0
=>y-x=3 [so,we check for "y" 4....5.....6 voila!! Now that makes x=3 ]
So, the no. is 36.
36 can be written as 2^2 x 3^2
So,we have 2 prime divisors.
The OA hence is B.

I hope the method is clear now.

P.S:-36 can straightaway strike your mind if you have done lot of problems regarding the digits reversal.
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