ranjithreddy.k9 wrote:Does the integer g have a factor f such that 1<f<g ?
1) g > 3!
2) 11!+2 <= g <= 11!+11
If the answer is NO -- if g does not have a factor between 1 and itself -- then g is prime.
Question rephrased: Is g prime?
Statement 1:
3! = 6.
If g=7, then g is prime.
If g=8, then g is not prime.
Insufficient.
Statement 2: 11!+2 <= g <= 11!+11
2 is a factor of 11! and of 2, so 2 is a factor of 11!+2.
3 is a factor of 11! and of 3, so 3 is a factor of 11!+3.
Continuing with this logic, every value of g between 11!+2 <= g <= 11!+11 will have a factor bigger than 1.
Thus, g is not prime.
Sufficient.
The correct answer is
BPrivate tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at
[email protected].
Student Review #1
Student Review #2
Student Review #3
