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Source: — Problem Solving |
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by hemant_rajput » Sun Feb 10, 2013 5:45 am
Soumita Ghosh wrote:Image

I chose C . Am I correct??
IMO C is the right choice. You wanted to choose 2 manager out of 3 manager and 3 employee out of 5 employee. so, if I'm doing right calculation and using correct logic, answer should be 4C2(manager)*5C3(employee).
I'm no expert, just trying to work on my skills. If I've made any mistakes please bear with me.
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by Brent@GMATPrepNow » Sun Feb 10, 2013 9:11 am
Take the task of building teams and break it into stages.

Stage 1: Select 2 managers.
Since the order of the selected managers does not matter, we can use combinations.
We can select 2 managers from 4 managers in 4C2 ways (6 ways).

Aside: If anyone is interested, we have a free video on calculating combinations (like 4C2) in your head: https://www.gmatprepnow.com/module/gmat-counting?id=789

Stage 2: Select 3 employees.
Since the order of the selected employees does not matter, we can use combinations.
We can select 3 employees from 5 employees in 5C3 ways (10 ways).

By the Fundamental Counting Principle (FCP) we can complete the 2 stages (and thus create a team) in (6)(10) ways ([spoiler]= 60 ways[/spoiler])

Answer = C

Cheers,
Brent

Aside: For more information about the FCP, we have a free video on the subject: https://www.gmatprepnow.com/module/gmat-counting?id=775
Brent Hanneson - Creator of GMATPrepNow.com
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