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did it lose the election?

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by sanju09 » Tue Apr 05, 2011 2:09 am
In an election contested by two parties, Party X secured 12% of the total votes more than Party Y. If party Y got 132,000 votes, by how many votes did it lose the election?
(A) 24,000
(B) 36,000
(C) 168,000
(D) 240,000
(E) 300,000
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by 6983manish » Tue Apr 05, 2011 2:24 am
sanju09 wrote:In an election contested by two parties, Party X secured 12% of the total votes more than Party Y. If party Y got 132,000 votes, by how many votes did it lose the election?
(A) 24,000
(B) 36,000
(C) 168,000
(D) 240,000
(E) 300,000

Let X party secured "x" votes.
Y party secured 132000 votes.

x-132000 = (12/100)* ( x + 132000 )
x-132000 = 0.12x + 15840
0.88x = 133584
x = 168000

Votes by Y lost the election = 168000 - 132000 = 36000

IMO B
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by Anurag@Gurome » Tue Apr 05, 2011 2:49 am
sanju09 wrote:In an election contested by two parties, Party X secured 12% of the total votes more than Party Y. If party Y got 132,000 votes, by how many votes did it lose the election?
(A) 24,000
(B) 36,000
(C) 168,000
(D) 240,000
(E) 300,000
Let total votes secured by Party X = x%
Then total votes secured by Party Y = (x - 12)%
Then, x + (x - 12)% = 100% implies 2x = 112 or x = 56%
This implies Party Y secured = 56 - 12 = 44% votes
Let total votes = T
Then 44% of T = 132,000
T = 132000/0.44 = 3,00,000 implies Total no. of votes = 3,00,000
So, Party Y lost the election by 12% of 3,00,000 = 0.12 * = 36,000 votes

The correct answer is B.
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