\(\dfrac{(x^4y^3)^{-2}}{(x^3y^2)^{-4}}=\)

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Vincen: Legendary Member; Posts: 2898; Joined: Thu Sep 07, 2017 2:49 pm; Thanked: 6 times; Followed by:5 members

\(\dfrac{(x^4y^3)^{-2}}{(x^3y^2)^{-4}}=\)

by Vincen » Mon Nov 09, 2020 7:48 am

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\(\dfrac{(x^4y^3)^{-2}}{(x^3y^2)^{-4}}=\)

A. \(x^{-4}y^{-2}\)

B. \(xy\)

C. \(x^3y^3\)

D. \(x^2y^2\)

E. \(x^4y^2\)

Answer: E

Source: Veritas Prep

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Source: Beat The GMAT — Problem Solving | Mon Nov 09, 2020 7:48 am

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