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Start the plan\(\dfrac{(x^4y^3)^{-2}}{(x^3y^2)^{-4}}=\)
A. \(x^{-4}y^{-2}\)
B. \(xy\)
C. \(x^3y^3\)
D. \(x^2y^2\)
E. \(x^4y^2\)
Answer: E
Source: Veritas Prep
A. \(x^{-4}y^{-2}\)
B. \(xy\)
C. \(x^3y^3\)
D. \(x^2y^2\)
E. \(x^4y^2\)
Answer: E
Source: Veritas Prep
