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defective chips

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by sanju09 » Tue Apr 07, 2009 4:27 am
A computer chip manufacturer expects the ratio of the number of defective chips to the total number of chips in all future shipments to equal the corresponding ratio for shipments S1, S2, S3 and S4 combined, as shown in the following table (read in order). What is the expected number of defective chips in a shipment of 60,000 chips?

Shipment: S1 S2 S3 S4
Number of defective chips in the shipment: 2 5 6 4
Total number of chips in the shipment: 5,000 12,000 18,000 16,000
A. 14
B. 20
C. 22
D. 24
E. 25

OA B
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by moutar » Tue Apr 07, 2009 4:37 am
Ratio is:

total number of defects:total number of chips (000s)

(2+5+6+4):(5+12+18+16)
= 17:51
= 1:3

So for 60,000 ratio is 20:60 so number of defective chips = 20 B.
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by sanju09 » Tue Apr 07, 2009 4:53 am
moutar wrote:Ratio is:

total number of defects:total number of chips (000s)

(2+5+6+4):(5+12+18+16)
= 17:51
= 1:3

So for 60,000 ratio is 20:60 so number of defective chips = 20 B.
this explanation doesn't seem to be convincing, moutar; better try again to make it comprehensive to one and all, it's a pre-mature display of some good work by you; leave space between ':' sign and start bracket '(' to avoid :(
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by moutar » Tue Apr 07, 2009 4:58 am
sanju09 wrote:
this explanation doesn't seem to be convincing, moutar; better try again to make it comprehensive to one and all, it's a pre-mature display of some good work by you; leave space between ':' sign and start bracket '(' to avoid :(
"the ratio of the number of defective chips to the total number of chips in all future shipments to equal the corresponding ratio for shipments S1, S2, S3 and S4 combined"

total number of defects:total number of chips

(2+5+6+4) : (5000+12000+18000+16000)
= 17:51000
= 1:3000

So for 60,000 ratio is 20:60000 so number of defective chips = 20 B.

I don't see what was wrong with the answer I gave before. It was perfectly logical and systematic like I try to make all my answers. Sorry about the smilie. I hate those things.
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by sanju09 » Tue Apr 07, 2009 5:11 am
nothing was wrong with your answer, it only needed supportive reasoning, like why 1:3 is same as 20:60000 etc..., or may be grammar somewhere, like writing 'defects' for 'defective', not much though :)

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by Anaira Mitch » Sat Jan 14, 2017 12:59 pm
(2+5+6+4)/(5000+12000+18000+16000)*60000 = 20
Answer is B
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by Brent@GMATPrepNow » Sat Jan 14, 2017 1:57 pm
Shipment / Number of Defective Chips in the Shipment / Total number of Chips in the Shipment
S1 / 2 / 5,000
S2 / 5 / 12,000
S3 / 6 / 18,000
S4 / 4 / 16,000

A computer chip manufacturer expects the ratio of the number of defective chips to the total number of chips in all the future shipments to equal the corresponding rate for shipments S1, S2, S3, and S4 combined, as shown in the table above. What is the expected number of defective chips in the shipment of 60,000 chips?

A) 14

B) 20

C) 22

D) 24

E) 25
Let's find some TOTALS for all 4 shipments combined.
There are 51,000 chips altogether
There are 17 defective chips altogether.

So, 17/51000 of the chips are defective. (notice that 17 divides nicely into 51000!)
SIMPLIFY: 1/3000 of the chips are defective

So, if we have a shipment of 60,000 chips, 1/3000 of them will be defective.
(1/3000)(60,000) = 20 defective chips

Answer: B

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by Scott@TargetTestPrep » Thu Jan 19, 2017 4:46 pm
sanju09 wrote:A computer chip manufacturer expects the ratio of the number of defective chips to the total number of chips in all future shipments to equal the corresponding ratio for shipments S1, S2, S3 and S4 combined, as shown in the following table (read in order). What is the expected number of defective chips in a shipment of 60,000 chips?

Shipment: S1 S2 S3 S4
Number of defective chips in the shipment: 2 5 6 4
Total number of chips in the shipment: 5,000 12,000 18,000 16,000
A. 14
B. 20
C. 22
D. 24
E. 25

We are given the following:

S1: 2 defective chips out of 5,000 total

S2: 5 defective chips out of 12,000 total

S3: 6 defective chips out of 18,000 total

S4: 4 defective chips out of 16,000 total

The ratio of the number of defective chips to total chips is:

(2 + 5 + 6 + 4)/(5,000 + 12,000 + 18,000 + 16,000)

17/51,000 = 1/3,000

We see that we would expect 1 chip out of every 3,000 chips to be defective.

We can set up a proportion to determine the number of defective chips that we would expect in a 60,000 shipment of chips.

1/3,000 = x/60,000

60,000 = 3,000x

x = 20 chips

Answer: B

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by Matt@VeritasPrep » Thu Jan 19, 2017 6:42 pm
This one seems below average difficulty for the modern GMAT, so be wary of that if you're using it today. (It was probably an average-ish difficulty question in 2009 when it was first posted, though.)
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