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by advita » Wed Jan 19, 2011 9:29 pm
The 20 of September 1990 was Thursday. What day was the 19th of September 1987,(note that 1988 was a leap-year).

Monday
Tuesday
Wednesday
Thursday
Friday
saturday


pl explain your logic/way to proceed...thanks.
Last edited by advita on Thu Jan 20, 2011 2:11 am, edited 1 time in total.
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by arora007 » Wed Jan 19, 2011 9:52 pm
(365*3) +1 = 1096

If today is thursday, when i go 7 days behind today it would be a wednesday.

now 1092 is the nearest multiple of 7.

so 1092 days behind 20th sept 1990 would be wednesday and 1096 days behind would be SATURDAY
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by Rahul@gurome » Thu Jan 20, 2011 2:01 am
The question has some problem with the option.
The answer is indeed Saturday.

Though the solution provided by arora007 is correct and elegant, I want to add some thumb rules for these types of problems which some of you may find useful.

A 30 day month = 30 days = (7*4 + 2) days --> 2 extra days
A 31 day month = 31 days = (7*4 + 3) days --> 3 extra days
A normal year = 365 days = (7*52 + 1) days --> 1 extra day
A leap year = 366 days = (7*52 + 2) days --> 2 extra days

In this case, the difference is equal to 2 normal years, 1 leap year and 1 day. Which is equivalent to (2*1 + 1*2 + 1) = 5 extra days. Hence we have to go 5 days back from a Thursday, which is indeed Saturday.
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by advita » Thu Jan 20, 2011 2:09 am
thanks rahul and arora...

yeah answer is saturday...!!!

(option must include saturday..it was typo..edited above.)
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