BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

data sufficiency

Problem Solving — algebra and arithmetic (GMAT Focus Edition)
Expert replies
by Kim9876Zey » Thu Jun 21, 2012 11:51 am
In the xy-plane, at what two points does the graph of y=(x+a)(x+b) intersect the x-axis?
1. a+b=1
2. the graph intersects the y-axis at (0,-6)

correct answer is both statement together

I am having a hard time placing y=(x+a)(x+b) with option one
Join the discussion
Source: — Quantitative Reasoning |

by Jim@StratusPrep » Thu Jun 21, 2012 12:09 pm
From the statement, we know that the parabola crosses the x-axis when x=a or when x=b, because y will then equal 0.

1) a and b can be anything.
2) we know that a or b = 6

Together, we know that the two possible values for a and b are 6 and -5. It doesn't matter which is which, because we know the two points. The two points are then (0,-6) and (0,5).
GMAT Answers provides a world class adaptive learning platform.
-- Push button course navigation to simplify planning
-- Daily assignments to fit your exam timeline
-- Organized review that is tailored based on your abiility
-- 1,000s of unique GMAT questions
-- 100s of handwritten 'digital flip books' for OG questions
-- 100% Free Trial and less than $20 per month after.
-- Free GMAT Quantitative Review

Image
Join the discussion

by jcnasia » Thu Jun 21, 2012 7:26 pm
y = (x + a)(x + b)
y = x^2 + ax + bx + ab
y = x^2 + (a+b)x + ab

The prompt tells us that it crosses y-axis at (0,-6), therefore:
-6 = 0^2 + 0 + ab
-6 = ab

And, to figure out when this equation crosses the x-axis, we set y = 0, and solve the equation:
0 = (x+a)(x+b)
x = -a or -b

So in order to figure out what a and b are equal to, I need to find two numbers that add up to 1 (since a + b = 1) and multiply together to get -6 (since ab = -6). I can do this in my head. I hope you can do.

(This is my mind thinking...)
Since they multiply together to get -6, I know that one is positive and and one is negative.
Since they add up to 1 and one is negative and one is positive, I know that their respective absolute values have a difference of 1. And since, they add up to 1 and not -1, I know that the absolute value of the positive number is bigger than the absolute value of the negative number.

So, what two numbers multiply together to get 6? And have a difference of 1?
3 and 2!

So 3 and 2 are the absolute values of a and b.

And since they need to add up to 1, then a and b are 3 and -2

Thus, x = -3 or 2 (since x = -a or -b)
The intersection points are (-3,0) and (2,0).
Join the discussion

by jcnasia » Thu Jun 21, 2012 7:33 pm
Jim@StratusPrep wrote:From the statement, we know that the parabola crosses the x-axis when x=a or when x=b, because y will then equal 0.

1) a and b can be anything.
2) we know that a or b = 6

Together, we know that the two possible values for a and b are 6 and -5. It doesn't matter which is which, because we know the two points. The two points are then (0,-6) and (0,5).
This is incorrect.
First of all, x = -a or x = -b when y = 0.
Second, a and b can't be anything. They have to add up to 1 and multiply together to get -6.
Third, neither a nor b = 6.
Fourth, (0,-6) and (0,5) aren't even on the x-axis. They're on the y-axis.
Join the discussion