ABCD is a cyclic quadrilateral whose diagonals intersect at point E. If angleDBC = 70, BAC = 30, what will be angle BCD.
A:30
B:70
C:80
D:100
E:150
A:30
B:70
C:80
D:100
E:150
Is it C?
OA?
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Cyclic Quadrilateral
Source: Beat The GMAT — Problem Solving |
yup.here u go
dac = dbc (a chord in a circle subtends equal angle at the circle)
so dac = dbc = 70
bad = dac + bac = 70 + 30 = 100
bad + bcd = 180
so, bcd = 180 - bad = 180 - 100 = 80.
Now u asked for the expln.,I know this is correct .
u can draw on a sheet of paper and understand wat i have written.
Sorry for explaining in short.
i am hadrcore engineer.cant help. :roll:
dac = dbc (a chord in a circle subtends equal angle at the circle)
so dac = dbc = 70
bad = dac + bac = 70 + 30 = 100
bad + bcd = 180
so, bcd = 180 - bad = 180 - 100 = 80.
Now u asked for the expln.,I know this is correct .
u can draw on a sheet of paper and understand wat i have written.
Sorry for explaining in short.
i am hadrcore engineer.cant help. :roll:
