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Cubes - OG 12th edition - Q # 11

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by sars72 » Mon Feb 01, 2010 10:07 am
what seems to be the problem?

cube root of 10^-6 = (10^-6)^(1/3) = (10)^(-6*1/3) = 10^-2
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by ajith » Mon Feb 01, 2010 10:16 am
bhumika.k.shah wrote:how did u get cube root of 10 ^ -6 as 10^-2 ?????
10^-6 = 1/1000000 = 1/10*1/10*1/10*1/10*1/10*1/10

cube root of a*a*a*a*a*a = a*a

cube root of 10^-6 = 1/10*1/10 = 1/10^2 = 10^-2
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by thephoenix » Mon Feb 01, 2010 10:17 am
sqrt(cube root(.000064))

.000064=64*10^-6=4^3*10^-6
taking cube root bth side=4*10^-2
taking sqrt 2*10^-1=2/10=0.2

cube root of 10^-6=[10]^(-6/3)=10^-2
hth
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