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where above, heavens?gmatmachoman wrote:If the figure above is a cube, and A, B and C are
midpoints on the edges of the cube, what is the
measure of L ABC?
(A) 30
(B) 45
(C) 60
(D) 90
(E) 120
Hey sanju.....sanju09 wrote:where above, heavens?gmatmachoman wrote:If the figure above is a cube, and A, B and C are
midpoints on the edges of the cube, what is the
measure of L ABC?
(A) 30
(B) 45
(C) 60
(D) 90
(E) 120
Which three edges one need to consider, mate? A cube has 12 distinct edges of same length, I believe. A schematic diagram above could have made the mystery solved.gmatmachoman wrote:Hey sanju.....sanju09 wrote:where above, heavens?gmatmachoman wrote:If the figure above is a cube, and A, B and C are
midpoints on the edges of the cube, what is the
measure of L ABC?
(A) 30
(B) 45
(C) 60
(D) 90
(E) 120
I am not sure if it is Heaven's..But pretty much invisible.....But y do u need a diagram? Try solving without it!
I refuse to solve the question without a diagram. Mr Govardhan - Gimme my diagram!gmatmachoman wrote:If the figure above is a cube, and A, B and C are
midpoints on the edges of the cube, what is the
measure of L ABC?
(A) 30
(B) 45
(C) 60
(D) 90
(E) 120
but how can we ever ignore what is written between the lines of the stem on GMAT, why shouldn't we request gmatmachoman to edit it once, it's no crime herekstv wrote:In the absence of diagram if I try thinking in 2D. A right angle isosceles can be made by joining the mid points of the adjacent edges.
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