Live GMAT classes with Target Test Prep start Nov 21 and Nov 22. First class free.

See classes
Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

Newsweek Readers’ Choice Awards 2026 winner: Target Test Prep, #1 Test Prep

Target Test Prep was voted #1 Best Test Prep in the 2026 Newsweek Readers’ Choice™ Awards.

★★★★★5.0563 reviews
GMATLiveTeachStarts Nov 22
Josh Braslow, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Josh Braslow, 20+ years in test prep

Nov 22 · Josh Braslow
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemandStart anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

EXECUTIVE ASSESSMENT

with

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemandStart anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Counting....Right Triangles

Expert replies
by knight247 » Sat Oct 01, 2011 11:42 pm
Right triangle ABC is to be drawn in the xy-plane so that the right angle is at A and AB is parallel to the y-axis. If the x- and y-coordinates of A, B, and C are to be integers that are consistent with the inequalities -6 ≤ x ≤ 2 and 4 ≤ y ≤ 9 , then how many different triangles can be drawn that will meet these conditions?
A. 54
B. 432
C. 2160
D. 2916
E. 148,824

OA C. Detailed explanations would be appreciated.
Join the discussion
Source: — Problem Solving |

by sl750 » Sun Oct 02, 2011 3:10 am
Total number of points for x coordinate = 9
Total number of points for y coordinate = 6

For point A, we have 9*6 ways to chose the x and y coordinate
For point B, only the y coordinate is different and we cannot use the same y coordinate as used by point A, so we have 9*5 ways to chose the x and y coordinate
For point C, only the x coordinate is different and we cannot use the same x coordinate as used by point A, so we have 8*6 ways to chose the x and y coordinate

Therefore, number of ways to create different right triangles is 9*6*5*8 =2160
Join the discussion

by GMATGuruNY » Sun Oct 02, 2011 3:17 am
knight247 wrote:Right triangle ABC is to be drawn in the xy-plane so that the right angle is at A and AB is parallel to the y-axis. If the x- and y-coordinates of A, B, and C are to be integers that are consistent with the inequalities -6 ≤ x ≤ 2 and 4 ≤ y ≤ 9 , then how many different triangles can be drawn that will meet these conditions?
A. 54
B. 432
C. 2160
D. 2916
E. 148,824

OA C. Detailed explanations would be appreciated.
When a question asks for the number of triangles that can be constructed, it's not a geometry question but a combinations question. Why? Because a triangle is a combination of 3 points.

We need to determine how many ways we can combine A, B and C to form a triangle that satisfies all the conditions given.
For each point, we need to choose an x value and a y value.

Point A:
x value: -6≤x≤2, giving us 9 choices.
y value: 4≤y≤9, giving us 6 choices.

To combine our choices for x with our choices for y, we multiply:
9*6 = 54.

Point C:
x value: In order to construct a right triangle, C has to have the same x coordinate as A (so that C is directly above A and we get a right angle). So we have only 1 choice for x: it must be the same integer that we chose for A's x value.

y value: If A and C share the same x value, they can't have the same y value, or they will be the same point. We used 1 of our 6 choices for y when we chose A, so we have 6-1 = 5 choices for C's y value.

To combine our choices for x with our choices for y, we multiply:
1*5 = 5.

Point B:
y value: For AB to be parallel to the x axis, A and B have to share the same y value. So the number of choices for y is 1; it must be the same integer that we chose for A's y value.

x value: If A and B share the same y value, they can't have the same x value, or they will be the same point. We used 1 of our 9 choices for x when we chose A, so we have 9-1 = 8 choices for B's x value.

To combine our choices for x with our choices for y, we multiply:
8*1 = 8.

Now we need to count how many ways A, B and C can be combined to form a triangle.
To combine our choices for A with our choices for B and C, we multiply:
54*5*8 = 2160.

The correct answer is C.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Join the discussion

by cmal » Mon Oct 17, 2011 1:18 am
Hey wouldnt this be something like this

15 points in total =9+6
15c3=455
if they are straight lines on the y axis or x-axis

hence

15c3-(9-6)?
=440
so i would pick B
Join the discussion