Answer should be between D and E.

We know prices for two nuts out of five for x grams each. Thus, we add them to get Rs. 4.6.

So, the answer has to be something which is greater than Rs. 4.6 and thus, eliminate A, B and C.

Can you site the source of this problem? This problem seems to be custom made and doesnot come from a official source.

Anyways, eager to see the answer!

neya wrote:A store sells five different kinds of nuts. If it is possible to buys x grams of the most expensive nuts for Rs. 3.20 and x grams of the cheapest nuts for Rs. 1.40 then which of the following could be the cost of purchasing a mixture containing x grams of each type of nut.?
(a) Rs. 1.76
(b) Rs. 2.84
(C) Rs. 3.54
(d) Rs. 13.60
(e) Rs. 16

If each type of the 5 types of nuts is as expensive as the most expensive type of nuts, then x pounds of each type of nuts will cost 5 * $3.20 = $16.00. Similarly, if each type of the 5 types of nuts is as cheap as the cheapest type of nuts, then x pounds of each type of nuts will cost 5 * $1.40 = $7.00. Since not all of the 5 types are as expensive as the most expensive type or as cheap as the cheapest type of nuts, therefore, the cost must be between $7.00 and $16.00. The only number in the answer choices that is between these two amounts is choice D: $13.60.

Answer: D