IMO 160.
Number of factors of [600 = 2^3 * 3 * 5^2] = 24
Just listing the beginning 1,2,3,4,5,6,8,10,12..... 24 factors
Outta these 2, 3, and 5 are Prime. So rest other factors can be multiple of these 3 primes.
We need to find the co-primes (No which does not have a common factor with 600)
All multiples of 2 will have a common factor with 600. So 2*300 = 600 We can discard 300
Remaining 600-300 = 300
All multiples of 3 will have a common factor with 600. So 3*200 / 2 = 100 discarded (divided by 2 because we have already taken care of multiple of 2, This only includes 3,9,15, etc. but not 6,12,...)
Remaining 300-100 = 200
All multiples of 5. I could not find way for this

discard 5,25,35,55,65,85,95
105,115,145,155,175,185 = 13 in 200 then 39 in 600.
Thus 200 -39 = 161.
I think 600 has been included in 161. So discard that 160.
Not sure

If the problem is Easy Respect it, if the problem is tough Attack it