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Source: — Data Sufficiency |
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by sam2304 » Mon Jan 30, 2012 8:49 am
Is it E ?

1.No info about the eqn of line. Line may be anywhere INSUFF
2.No info about circle's radius. Circle may be too small or radius < 3. INSUFF

Combining 1 and 2 we can say that line might cross through the circle or be tangential to the circle. Not sure if we can say tangents intersect the circle. What is the OA ? Can some experts help to solve this ?
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by MakeUrTimeCount » Tue Jan 31, 2012 5:33 am
@Sam:
Yes, tangent intersect the circle.
Intersect means - Any points of contact.

The answer to the question is E indeed.

A) Does not say anything about line.
B) Does not say anything about Circle.

Using Both,
1) We still don't know the slope of the line.
2) The distance of point (3,3) is way more than the radius of the circle.
The circle may intersect the points which satisfies the equation:
x^2 + y^2 <= 3^2

Points (3,3) makes x^2 + y^2 = 2. 3^2
Which is double the distance of circle radius with centre at (0,0).
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by Whitney Garner » Tue Jan 31, 2012 11:06 am
sam2304 wrote:Is it E ?

1.No info about the eqn of line. Line may be anywhere INSUFF
2.No info about circle's radius. Circle may be too small or radius < 3. INSUFF

Combining 1 and 2 we can say that line might cross through the circle or be tangential to the circle. Not sure if we can say tangents intersect the circle. What is the OA ? Can some experts help to solve this ?
The answer is indeed E. Stm(1) nothing about the line, Stm(2) nothing about the circle. Now, sketch the coordinate plane on your paper with a circle centered at (0,0). With a radius of 3, it will have intersects at (0,3), (0,-3), (3,0) and (-3,0). Now draw the point (3,3) - you will see that this is actually OUTSIDE the circle, NOT on the edge (the question is trying to trick you). To confirm, the distance from the point (3,3) to the origin (0,0) = sqrt(3^2 + 3^2) = sqrt(18) = 3sqrt(2) so LONGER than the radius of 3.

Hope this helps!
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