Live GMAT classes with Target Test Prep start Nov 21 and Nov 22. First class free.

See classes
Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

Newsweek Readers’ Choice Awards 2026 winner: Target Test Prep, #1 Test Prep

Target Test Prep was voted #1 Best Test Prep in the 2026 Newsweek Readers’ Choice™ Awards.

★★★★★5.0563 reviews
GMATLiveTeachStarts Nov 22
Josh Braslow, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Josh Braslow, 20+ years in test prep

Nov 22 · Josh Braslow
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemandStart anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

EXECUTIVE ASSESSMENT

with

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemandStart anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Coordinate Geometry

Expert replies
by Brent@GMATPrepNow » Wed Dec 17, 2008 9:17 am
A triangle has vertices at (0,2), (4,7) and (6,0).
What is the area of the triangle?

(A) 19
(B) 20
(C) 21
(D) 22
(E) 23

Answer: A
Brent Hanneson - Creator of GMATPrepNow.com
Image
Join the discussion
Source: — Problem Solving |

by amitabhprasad » Wed Dec 17, 2008 9:29 am
Area of Rectangle = 7*6
Minus areas of 3 triangle =
1/2(6*2)=6
+1/2(2*7)=7+
+1/2(4*5) = 10
==> 42-23 = 19
Join the discussion

by vittalgmat » Wed Dec 17, 2008 10:54 am
The formula for the area of triangle given the 3 coordinates is:

1/2 Abs [ (x1-x2)(y2-y3) - (y1-y2)(x2-x3) ]



Here (x1, y1), (x2,y2) and (x3,y3) are (0,2), (4,7) and (6,0).
(however anyone can be (x1,y1) etc. )
Substituting and simplifying,
we get 0.5 * |-28 -10|

=38/2 = 19

HT helps
Join the discussion

by parallel_chase » Wed Dec 17, 2008 10:57 am
area of the triangle in a coordinate system

1/2 l (x2-x1)(y3-y2) + (y2-y1)(x3-x2) l

1/2 l(4-0)(7-0) + (7-2)(6-4)l

1/2 l28 + 10l

1/2 * 38 = 19

Hence A.
No rest for the Wicked....
Join the discussion

by Brent@GMATPrepNow » Wed Dec 17, 2008 3:52 pm
The formula for the area of triangle given the 3 coordinates is:

1/2 Abs [ (x1-x2)(y2-y3) - (y1-y2)(x2-x3) ]
Wow, I can't say that I've seen that formula before.
Very interesting.
Brent Hanneson - Creator of GMATPrepNow.com
Image
Join the discussion

by mrsmarthi » Wed Dec 17, 2008 9:00 pm
My ans will be A - 19. But the approach to the solution is different.

With the the vertices of the triangle, I noticed that one point is on the X axis (6,0) and one on y axis (0,2) and the other point in 1 Quandrant.

I tried to construct a Trapeziod with the points A(0,0), B(6,0), C(4,7)(these are two of the vertices of the trianle in question)and D(0,7). Here CD is parallel to AB, AB and CD are the bases and AD is the height of the trapeziod. Now area of the trapoziod is 1/2(sum of the bases) * height = 1/2(6+4) * 7 = 35.

Let the E(0,2) be the third vertex which lies on AD. I tried finding the area of traingle AEB and area of triangle ECD which are the right triangles.

Area of triangle AEB = 1/2 * 6 * 2 = 6
Area of Triangle ECD = 1/2 * 4 * 5 = 10.

So Area of traingle BCE(which is our question) is Area of trapeziod ABCD - area of traingle AEB and area of triangle ECD.

35-10-6 = 19.

So my Ans is 19.

My apologies for not showing in a diagram. I don't know how can I put that in the diagram format. But if you try to draw the figure, you should be able to understand the points.

Brent Hanneson,

Thank you for posting some good questions. When you said that you are not aware of the formula that other posters have made, I realised there should be a way. And here is my way. Taking the inspiration of Thinking Out of the Box. [/img]
Join the discussion

by Brent@GMATPrepNow » Wed Dec 17, 2008 10:15 pm
I like this technique, mrsmarthi.
Rather than find the area of the rectangle and subtract the areas of the three triangles around the target triangle, you found the area of the trapezoid and subtracted only 2 triangles.

That's what I love about GMAT questions: 1 question and we already have 3 distinct solutions.

Any more out there?
Brent Hanneson - Creator of GMATPrepNow.com
Image
Join the discussion

Re: Coordinate Geometry

by logitech » Wed Dec 17, 2008 11:14 pm
Brent Hanneson wrote:A triangle has vertices at (0,2), (4,7) and (6,0).
What is the area of the triangle?

(A) 19
(B) 20
(C) 21
(D) 22
(E) 23

Answer: A
Okay here is the life safer method for those who are not good at math. Put these three points on your paper ( It has grids ) Draw your triangle and count the squares! :-) You will be surprised!
LGTCH
---------------------
"DON'T LET ANYONE STEAL YOUR DREAM!"
Join the discussion