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Consecutive odd integers

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by Anurag@Gurome » Sat Jan 15, 2011 9:20 pm
Ramalakshmi wrote:Find n if n is the sum of consecutive odd numbers whose sum is 81?
Please check the question.
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by anshumishra » Sat Jan 15, 2011 9:26 pm
Ramalakshmi wrote:Find n if n is the sum of consecutive odd numbers whose sum is 81?

Can anyone help me out with this problem
As Anurag has suggested check the problem, it is not properly written.
If the consecutive numbers start from 1, means the series is something like (1,3,5...), then

Sum of n terms = n^2 = 81
=> n = 9.

BUT, if the question is different , please update it.
You may use this formula :

Sum = n/2[2a+(n-1)*2], where "a" is the first term
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by Ramalakshmi » Sat Jan 15, 2011 9:41 pm
The question is correct .....


Find n if n is the sum of consecutive odd positive numbers whose sum is 81?


n^2=81

9 is the answer


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by Anurag@Gurome » Sat Jan 15, 2011 10:07 pm
Ramalakshmi wrote:The question is correct .....

Find n if n is the sum of consecutive odd positive numbers whose sum is 81?
There is no way the question is correct.
If "n is the sum of consecutive odd positive numbers whose sum is 81, then the value of n must be 81 itself!

If 9 is the answer then the proper question should be something like : Find n if the sum of first n consecutive odd positive integers is 81.

In that case, the integers are 1, 3, 5, ..., (2n - 1)
The sum = n*[ 1 + (2n - 1)]/2 = n^2

=> n^2 = 8
=> n = 9
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