a-b+c>a+b-c?
You can cancel out 'a' from both sides. So you'll get c-b>b-c?
So basically the question is asking is c>b?
St 1 b is negative. No info about C INSUFF
St2: c is positive. No info about B INSUFF
1+2 we know b<c.
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Confusing OA
Source: Beat The GMAT — Data Sufficiency |
Even Im getting C
a-b+c>a+b-c?
You can cancel out 'a' from both sides. So you'll get c-b>b-c?
So basically the question is asking is c>b?
St 1 b is negative. No info about C INSUFF
St2: c is positive. No info about B INSUFF
1+2 we know b<c.
a-b+c>a+b-c?
You can cancel out 'a' from both sides. So you'll get c-b>b-c?
So basically the question is asking is c>b?
St 1 b is negative. No info about C INSUFF
St2: c is positive. No info about B INSUFF
1+2 we know b<c.
OA should be C
looking at the question another way, it is asking
whether
-b +c > b -c ?
=> -(b -c) > b -c ?
This can only happen if we know b and c.
So C
looking at the question another way, it is asking
whether
-b +c > b -c ?
=> -(b -c) > b -c ?
This can only happen if we know b and c.
So C
unless i missed something, i got D
a-b+c > a+b-c
this comes to -b+c>b-c
c>2b-c
0>2b-2c
therefore c>b
a-(b-c)>a+(b-c)
a and subtracting any negative number will always be more than A + any negative number..however i am not sure if i have worked out the inequalities right.
a-b+c > a+b-c
this comes to -b+c>b-c
c>2b-c
0>2b-2c
therefore c>b
a-(b-c)>a+(b-c)
a and subtracting any negative number will always be more than A + any negative number..however i am not sure if i have worked out the inequalities right.
OA is definitely C. This is an OG problem. I've done OG so many damn times that I can guarantee that this question is between 80 - 100 in the 11th edition.
-
ronniecoleman
- Legendary Member
- Posts: 546
- Location: New Delhi , India
- Thanked: 13 times
if a, b, c are integers, is a-b+c>a+b-c?
(i)b<0
(ii) c>0
Since b is negatvie
so -b > b
add anything a -b > a+ b
now if we add c ( which can be both positive or negative we don't know)
so II is required to understand the sign of c.
IMO C
OA is wrong!!
(i)b<0
(ii) c>0
Since b is negatvie
so -b > b
add anything a -b > a+ b
now if we add c ( which can be both positive or negative we don't know)
so II is required to understand the sign of c.
IMO C
OA is wrong!!
Admission champion, Hauz khaz
011-27565856
011-27565856
again, isnt a-(b-c)> a+(b-c)...we dont need any of the statements to figure that c>b..so b-c will always be negative...A minus a negative will be additive.ronniecoleman wrote:if a, b, c are integers, is a-b+c>a+b-c?
(i)b<0
(ii) c>0
Since b is negatvie
so -b > b
add anything a -b > a+ b
now if we add c ( which can be both positive or negative we don't know)
so II is required to understand the sign of c.
IMO C
OA is wrong!!
No, a-(b-c)> a+(b-c) is not given in the question, ie it is not considered true. The question is asking you IF a-(b-c)> a+(b-c)?again, isnt a-(b-c)> a+(b-c)
hypik21 wrote: again, isnt a-(b-c)> a+(b-c)...we dont need any of the statements to figure that c>b..so b-c will always be negative...A minus a negative will be additive.
Even with this, OA cant be "D" as you mentioned...
Infact, we have to answer this..and not take this as a fact
This question is from my prepcourses. I think I made a mistake when I wrote down answers.
However, my answer is simslar to uor Math Gurus! This means I am correct!
However, my answer is simslar to uor Math Gurus! This means I am correct!
