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Confusing OA

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by 4meonly » Mon Dec 22, 2008 11:49 am
if a, b, c are integers, is a-b+c>a+b-c?

(i)b<0
(ii) c>0

OA D
I got C
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Source: — Data Sufficiency |
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by mals24 » Mon Dec 22, 2008 12:14 pm
Even Im getting C

a-b+c>a+b-c?

You can cancel out 'a' from both sides. So you'll get c-b>b-c?
So basically the question is asking is c>b?

St 1 b is negative. No info about C INSUFF
St2: c is positive. No info about B INSUFF

1+2 we know b<c.


:?
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by parallel_chase » Mon Dec 22, 2008 12:24 pm
Answer should be C.

whats the source?
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by 4meonly » Mon Dec 22, 2008 12:25 pm
my logic was absolutely similar.
Guess we are right about C
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by vittalgmat » Mon Dec 22, 2008 12:56 pm
OA should be C

looking at the question another way, it is asking
whether
-b +c > b -c ?
=> -(b -c) > b -c ?

This can only happen if we know b and c.

So C
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by hypik21 » Mon Dec 22, 2008 1:49 pm
unless i missed something, i got D

a-b+c > a+b-c

this comes to -b+c>b-c
c>2b-c
0>2b-2c

therefore c>b

a-(b-c)>a+(b-c)

a and subtracting any negative number will always be more than A + any negative number..however i am not sure if i have worked out the inequalities right.
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by beater » Mon Dec 22, 2008 2:06 pm
OA is definitely C. This is an OG problem. I've done OG so many damn times that I can guarantee that this question is between 80 - 100 in the 11th edition.
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by ronniecoleman » Mon Dec 22, 2008 9:40 pm
if a, b, c are integers, is a-b+c>a+b-c?

(i)b<0
(ii) c>0

Since b is negatvie

so -b > b

add anything a -b > a+ b

now if we add c ( which can be both positive or negative we don't know)

so II is required to understand the sign of c.

IMO C

OA is wrong!!
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by hypik21 » Mon Dec 22, 2008 11:15 pm
ronniecoleman wrote:if a, b, c are integers, is a-b+c>a+b-c?

(i)b<0
(ii) c>0

Since b is negatvie

so -b > b

add anything a -b > a+ b

now if we add c ( which can be both positive or negative we don't know)

so II is required to understand the sign of c.

IMO C

OA is wrong!!
again, isnt a-(b-c)> a+(b-c)...we dont need any of the statements to figure that c>b..so b-c will always be negative...A minus a negative will be additive.
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by mals24 » Tue Dec 23, 2008 1:55 am
again, isnt a-(b-c)> a+(b-c)
No, a-(b-c)> a+(b-c) is not given in the question, ie it is not considered true. The question is asking you IF a-(b-c)> a+(b-c)?
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by vivek.kapoor83 » Tue Dec 23, 2008 1:59 am
IMO C...as everybdy calculated.
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by iamcste » Tue Dec 23, 2008 2:09 am
hypik21 wrote: again, isnt a-(b-c)> a+(b-c)...we dont need any of the statements to figure that c>b..so b-c will always be negative...A minus a negative will be additive.

Even with this, OA cant be "D" as you mentioned...

Infact, we have to answer this..and not take this as a fact
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by 4meonly » Tue Dec 23, 2008 3:08 am
This question is from my prepcourses. I think I made a mistake when I wrote down answers.
However, my answer is simslar to uor Math Gurus! This means I am correct!
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