sanju09 wrote:liferocks wrote:sanju09 wrote:liferocks wrote:let x be the number of application recommended by 2 person and y be the number of application recommended by 3 persons
for max common recomendation,
hence 30+x+2y=15+17+20 or x+2y=22
maximum y is 11..so 3 people can recommend at MAX 11
Not sure if the question is correct.Can you please check.
What exactly is happening here or do I really need rest now?
The question says first person can recommend 15 , second can 17 and third can 20,,but it does not says what is the minimum applications any person can recommended .So we can get what is the maximum recommendations not the minimum. That's why I thought question might not be correct .
The posted stuff has no doubt more than one shortcoming that avert us to call it a genuine GMAT PS, but I am asking what has made you write what’s in bold above, what was your previous interpretation like, and hence what!!
ok..this is how I got it
Since first person can recommend 15 , second can 17 and third can 20 maximum number of recomendation is 15+17+20=52
this will contain all application that has only one reco+ 2* all application that has two reco+ 3* all application that has 3 reco
which is nothing but 30+x+2y as per mentioned conventions
so 30+x+2y=52 or x+2y=22
now here if we want to maximize y,which is number of applications with 3 reco,x has to be minimised..minimum possible number is 0 and hence max y=11
“If you don't know where you are going, any road will get you there.”
Lewis Carroll
