This is a good one!

Rather than getting into formulas, let's think about it logically:

For the first person, we have 8 choices (we can pick anyone).

For the second person, we have 6 choices (we can pick anyone except the person already picked and his/her spouse).

For the third person, we have 4 choices (we can pick anyone except the two people already picked and their two spouses).

Thus, we have 192 different arrangements. But, since "order doesn't matter" in this case (e.g., a committee with Al, Bob, and Carl is the same as a committee with Carl, Bob, and Al), we have to divide.

Since we have three "items" in our calculation (the three committee members), we must divide 192 by 3! = 32.

Hope this helps!

Understood.. OA is 32