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by shilpaqueen » Sun Nov 21, 2010 10:54 am
A committee of 5 is to be chosen from a group of 9 children. What is the probality that there is atleast 1 girl in the commitee?
1) there are 8 boys and 1 girl in the group
2) there are 4 boys in the commitee
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Source: — Data Sufficiency |
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by clock60 » Sun Nov 21, 2010 12:45 pm
debatable question
to me 1 st is suffcient, we can calculate the prob of 1 girl and 4 boys
from 2 we know that 4 boys are already in committee, but we are not given that we have at least 1 girl to chose from to me it is possible that we have no girls at all, as we are given clearly only 9 children
my pick for A
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by shilpaqueen » Mon Nov 22, 2010 10:02 am
clock60 wrote:debatable question
to me 1 st is suffcient, we can calculate the prob of 1 girl and 4 boys
from 2 we know that 4 boys are already in committee, but we are not given that we have at least 1 girl to chose from to me it is possible that we have no girls at all, as we are given clearly only 9 children
my pick for A
The official answer is D
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by goyalsau » Tue Nov 23, 2010 3:36 am
shilpaqueen wrote:A committee of 5 is to be chosen from a group of 9 children. What is the probality that there is atleast 1 girl in the commitee?
1) there are 8 boys and 1 girl in the group
2) there are 4 boys in the commitee
I am Convinced that the answer should be D, But What if have this question on the Problem Solving Section,

Guys Please Explain How to solve it,
Saurabh Goyal
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by TOPGMAT » Wed Nov 24, 2010 11:08 pm
Hi math guru's
How can statement 2 be sufficient here ?

4 boys in the commitee...
there can be 8B and 1G in the group, or 7B and 2G in the group etc...
probablity changes as no of girls changes.
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