Answer is B.
If we can calculate all the odd integers below 500 with distinct digits and remove them from 250, would be the answer required.
Odd integers starting with 1 can be give as 1AB where A can take 9 values and B can take 4 values (from 1,3,5,7,9 we shd not consider 1 as we are trying to get all distinct digits)
so number of odd integers starting with 1 are 9*4 =36. The same condition holds tru for numbers starting with 3
Similarly numbers starting with 2,4 are 9*5 = 45 (respective places of A and B)
so total number of odd integers below 500 that are distinct are 36*2+ 45*2 = 162.
So the required answer = 250-162 =88
Regards,
Chetan
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