Combinations

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swerve: Legendary Member; Posts: 2525; Joined: Sun Oct 29, 2017 2:04 pm; Followed by:6 members

by swerve » Sun Dec 29, 2024 10:44 am

Timer

00:00

How many different $11-$letter arrangements are possible with the letters $aabbbbccccc?$

A. $11$
B. $45$
C. $90$
D. $6930$
E. $11!$

The OA is D

Source: Beat The GMAT — Problem Solving | Sun Dec 29, 2024 10:44 am

shawlless: Newbie | Next Rank: 10 Posts; Posts: 3; Joined: Wed Mar 27, 2024 2:55 am

by shawlless » Wed Jan 01, 2025 8:59 pm

Explain?

SanjuSimpleson: Newbie | Next Rank: 10 Posts; Posts: 4; Joined: Thu Dec 12, 2024 9:59 pm

by SanjuSimpleson » Thu Jan 16, 2025 2:55 am

$$\frac{11!}{2!4!5!}$$

$$\frac{11!}{2!4!5!}\ =\ 6930$$

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