combination

IMO B

Cans - Thanks can you please explain?

Hi,
Car1 can be selected from 8 cars in 8 ways
Car2 can be selected from 6 cars in 6 ways
Car3 can be selected from 4 cars in 4 ways
Order of the cars is unimportant. So, number of combinations is 8.6.4/3! = 32
(or)
Choose 3 colors from the 4 in 4C3 ways
For each color, we can choose either modelA or modelB in 2 ways.
So, number of combinations is 4C3.(2)^3 = 32

Hence, B

Cheers!

4 colors available. To select 3 cars with all different - 4C3 ways
for each color, 2 models. thus 2*2*2 =8
Total of 4C3*8 = 32