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by budetta4 » Wed Feb 17, 2010 2:59 am
if 3 boys and three girls must sit in a row of six chair but neither boys or girls are allowe to sit, how many different seating arrangemets can be made?

A 12
B 36
C72
D 180
E 360

could spmeone explain me how to solve it?
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by sadullaevd » Wed Feb 17, 2010 3:04 am
could you plz check question stem,

i cant understand it, guess others will also find it unclear.

thank you.
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by papgust » Wed Feb 17, 2010 3:05 am
Can you check the question? It doesn't sound logical. First, it says that boys and girls must in a row, but then it says that neither boys nor girls are allowed to sit.
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by thephoenix » Wed Feb 17, 2010 3:13 am
budetta4 wrote:if 3 boys and three girls must sit in a row of six chair but neither boys nor girls are allowed to sit together, how many different seating arrangemets can be made?

A 12
B 36
C72
D 180
E 360

could spmeone explain me how to solve it?
i guess the question is like the abve one

if yes than IMO B sud be the ans

3 boys can be placed in 3!=6 ways
in b/n three places 3 girls can seated in 3!=6 ways
tot=6*6=36
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by ajith » Wed Feb 17, 2010 3:31 am
budetta4 wrote:if 3 boys and three girls must sit in a row of six chair but neither boys or girls are allowed to sit together, how many different seating arrangements can be made?

A 12
B 36
C72
D 180
E 360

could someone explain me how to solve it?
_ _ _ _ _

We can either arrange boys in 1st , 3rd and 5th slot , or 2nd, 4th and 6th slot
Boys can be arranged within themselves in 6 ways
Girls can be arranged within themselves in 6 ways

Total no of ways = 2*6*6 = 72

C
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