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Re: Combination

by gabriel » Fri May 04, 2007 11:42 am
Cybermusings wrote:Please give detailed explanation with this question
Ok ... if micheal has already been selected the reamining 2 members of the team can be chosen in 5c2 ways and the other team can b chosen in 3c3 ways so total no. of committes that include micheal is 10 ...

now ... conbsider that micheal and anthony both are chosen so the third member of the team can be chosen in 4c1 ways .. so out of the 10 committes that can be formed including micheal, 4 also includes anthony.. so the answer is 4/10 .. that is 40% ...

PS ... feels good to be back on ( one of :D ) my fav forums ...
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