Combination / Permutation problem

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jessicamuniz: Junior | Next Rank: 30 Posts; Posts: 26; Joined: Thu Jul 17, 2008 1:02 pm

by jessicamuniz » Sat Nov 22, 2008 12:27 pm

Hi everybody, here is a questions. I got the answer but I would like to know your options. Thanks in advance.

Amanda goes to the toy store to buy 1 ball and 3 different board games. If the toy store is stoked with 3 types of balls and 6 types of board games, how many different selections of the items can Amanda make?
a. 9 b.12 c.14 d.15 e.60
ANS: E

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Source: Beat The GMAT — Problem Solving | Sat Nov 22, 2008 12:27 pm

Tryingmybest: Master | Next Rank: 500 Posts; Posts: 168; Joined: Thu Nov 13, 2008 4:34 am; Location: Pittsburgh; Thanked: 9 times

by Tryingmybest » Sat Nov 22, 2008 12:29 pm

Ans 60

3C1 * 6C3 = 60

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Abdulla: Master | Next Rank: 500 Posts; Posts: 328; Joined: Thu Aug 07, 2008 5:25 pm; Location: Philadelphia; Thanked: 4 times; GMAT Score:550

by Abdulla » Sat Nov 22, 2008 8:12 pm

Tryingmybest wrote:Ans 60

3C1 * 6C3 = 60

What is the meaning of C ( 3C1) ?

Abdulla

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hrishikesh05: Junior | Next Rank: 30 Posts; Posts: 28; Joined: Sat Jul 05, 2008 11:07 pm; Thanked: 2 times

by hrishikesh05 » Sat Nov 22, 2008 10:16 pm

C is the notation for combination

Check this link for more information on C

https://en.wikipedia.org/wiki/Mathematical_combination

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Abdulla: Master | Next Rank: 500 Posts; Posts: 328; Joined: Thu Aug 07, 2008 5:25 pm; Location: Philadelphia; Thanked: 4 times; GMAT Score:550

by Abdulla » Sat Nov 22, 2008 11:18 pm

Thanks bro

Abdulla

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Jeff@TargetTestPrep: GMAT Instructor; Posts: 1462; Joined: Thu Apr 09, 2015 9:34 amFollowed by: 22 members; Location: New York, NY; Thanked: 39 times

by Jeff@TargetTestPrep » Mon Jan 08, 2018 11:41 am

jessicamuniz wrote:Amanda goes to the toy store to buy 1 ball and 3 different board games. If the toy store is stoked with 3 types of balls and 6 types of board games, how many different selections of the items can Amanda make?
a. 9
b.12
c.14
d.15
e.60

Amanda can select a ball in 3C1 = 3 ways and she can selected a board game in 6C3 = 6!/[3!(6-3)!] = (6 x 5 x 4)/3! = (6 x 5 x 4)/(3 x 2 x 1) = 20. So, the total number of ways is 3 x 20 = 60.

Answer: E

Jeffrey Miller
Head of GMAT Instruction
[email protected]

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