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combination help

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Source: — Problem Solving |
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Joined: Tue Aug 07, 2007 1:45 amFollowed by: 1 member

by agps » Wed Sep 05, 2007 3:17 am
possible chairs = 5!/(2!*3!)=10 this because chair1, chair2 and chair2, chair1 is the same choice.

total combinations = combination of chairs * combination of tables
150 = 10*combination of tables
combination of tables=15

so x!/(2!*(x-2)!)=15, this simplifies to (x*(x-1))/2= 15 and to x^2-x-30=0
x=6 or x=-5, since you can't have a negative number of tables 6 is the answer (A)
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