College admission

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Viper83: Senior | Next Rank: 100 Posts; Posts: 67; Joined: Mon Aug 16, 2010 4:42 am

by Viper83 » Tue Nov 23, 2010 6:54 am

A admin officer predicts that 20% of the students who are accepted will not attend college. According to this prediction, how many students should be accepted to achieve a planned enrollment of x students?

a) 1.05x
b) 1.1x
c) 1.2x
d) 1.25x
e) 1.8x

D

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Source: Beat The GMAT — Problem Solving | Tue Nov 23, 2010 6:54 am

abhishekg21: Senior | Next Rank: 100 Posts; Posts: 49; Joined: Tue May 11, 2010 5:46 am; Thanked: 3 times

by abhishekg21 » Tue Nov 23, 2010 7:14 am

it means 80% of accepted students will join the college.
since 80 % of accepted students=x
so accepted students=1.25x

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Yes.WeCan: Senior | Next Rank: 100 Posts; Posts: 30; Joined: Wed Jan 13, 2010 7:20 amFollowed by: 1 member; Thanked: 1 times

by Yes.WeCan » Tue Nov 23, 2010 3:08 pm

Yield = 100%-20% = 80%
1/yield = amount of students to be accepted
1/0,8 = 1,25

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aippingw: Junior | Next Rank: 30 Posts; Posts: 16; Joined: Wed Feb 03, 2010 7:59 pm; Thanked: 2 times

by aippingw » Wed Nov 24, 2010 1:58 pm

I don't get it...
Can you guys please explain it once more?

Thanks!

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GMATGuruNY: GMAT Instructor; Posts: 15539; Joined: Tue May 25, 2010 12:04 pmFollowed by: 1906 members; Location: New York, NY; Thanked: 13060 times; GMAT Score:790

by GMATGuruNY » Wed Nov 24, 2010 2:20 pm

Viper83 wrote:A admin officer predicts that 20% of the students who are accepted will not attend college. According to this prediction, how many students should be accepted to achieve a planned enrollment of x students?

a) 1.05x
b) 1.1x
c) 1.2x
d) 1.25x
e) 1.8x

D

Plug in x=80. This represents the desired enrollment.
For an enrollment of 80 students, 100 must be accepted (since 20% will not attend college).
Now we plug x=80 (the desired enrollment) into all the answer choices to see which yields 100 (the number of students that must be accepted).

Only answer choice D works:
1.25*80 = 100.

The correct answer is D.

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aippingw: Junior | Next Rank: 30 Posts; Posts: 16; Joined: Wed Feb 03, 2010 7:59 pm; Thanked: 2 times

by aippingw » Thu Nov 25, 2010 8:58 am

Great !

Thank you so much for your help Guru!

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