abhasjha wrote:Rasheed bought two kinds of candy bars, chocolate and toffee, that came in packages of 2 bars each. He handed out 2/3 of the chocolate bars and 3/5 of the toffee bars. How many packages of chocolate bars did Rasheed buy?

1. Rasheed bought 1 fewer package of chocolate bars than toffee bars

2. Rasheed handed out the same number of each kind of candy bar

Strictly counting the bars, let's say c bars of chocolate and t bars of toffee were bought in total. When 2 c/3 + 3 t/5 is handed out, he's left with c/3 + 2 t/5 number of bars. What is t + c?

(1) With t - c fixed, we cannot fix t + c. Insufficient

(2) It tells that 2 c/3 = 3 t/5 or 10 c = 9 t. This again cannot fix t + c by itself. Insufficient

taken together

with t - c = 2 and 10 c = 9 t, t + c could be answered uniquely. Sufficient

[spoiler]C[/spoiler]

abhasjha wrote:Rasheed bought two kinds of candy bars, chocolate and toffee, that came in packages of 2 bars each. He handed out 2/3 of the chocolate bars and 3/5 of the toffee bars. How many packages of chocolate bars did Rasheed buy?

1. Rasheed bought 1 fewer package of chocolate bars than toffee bars

2. Rasheed handed out the same number of each kind of candy bar

1. C-T = 2 insufficient
2. 2C/3 = 3T/F

Combining sufficient
Hence C