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Master | Next Rank: 500 Posts
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by Suyog » Mon Nov 26, 2007 9:59 pm
A grocer bought 24kg of coffee beans at Price X. After a while 1/3 of the stock got spoiled so he sold rest for $200 per kg and made total profit of twice the cost. What must be price of X?
1. $66 2/3
2. $50 1/3
3. $44 4/9
4. $33 1/3
5. $24 1/2
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by syv11 » Mon Nov 26, 2007 10:31 pm
200*2/3*24-24*x = 2*x*24
400/3-x=2x
x=44.4444, 44 4/9
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by Suyog » Mon Nov 26, 2007 10:38 pm
dont know wot im missing...

1/3 * 24 = 8

24 - 8 = 16....thats not spoiled...

16 * 200 = 3200.. cost is 3200 / 2 = 1600

1600 / 24 = 66 2/3..

i think im missing something...but wot???
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by syv11 » Mon Nov 26, 2007 10:50 pm
You have revenues of 200*16=3200

Your cost depends on the price (x) you bought it

24x

Total profit: 2*24x

3200-24x=2*24x
3200=72x
x=44 4/9
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by mtr » Thu Nov 29, 2007 11:49 am
Suyog wrote:dont know wot im missing...

1/3 * 24 = 8

24 - 8 = 16....thats not spoiled...

16 * 200 = 3200.. cost is 3200 / 2 = 1600

1600 / 24 = 66 2/3..

i think im missing something...but wot???
You divided 3200 by 2 and it should be 3 since the profit was 2 times the cost. So the cost would be 1/3 of the 3200. Hope that helps.
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