BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

co rodinate geometry

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Newbie | Next Rank: 10 Posts
Posts: 5
Joined: Wed Apr 11, 2012 9:19 am
by priyank.hirani » Sun Apr 15, 2012 8:25 am
Lines n and p lie in the xy plane.Is the slope of line n less than the slpe of line p??

(1)Lines n and p intersect at (5,1)
(2)The y intercept of line n is greater than the y intercept of line p.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Data Sufficiency |
Junior | Next Rank: 30 Posts
Posts: 27
Joined: Sun Apr 08, 2012 5:38 am
Thanked: 20 times

by shubham_k » Sun Apr 15, 2012 8:48 am
Lines n and p lie in the xy plane.Is the slope of line n less than the slpe of line p??

(1)Lines n and p intersect at (5,1)

We cannot say anuything abt slope INSUFF

(2)The y intercept of line n is greater than the y intercept of line p.

Here also we can't say coz one slope may be -ve or lines may be parallel.

INSUFF

combine

eqn of n is y=m1 * x +c1

p is y=m2*x + c2

at (5,1) we ave

5m1 +c1 = 5m2 +c2

also c1 >c2

then for this to be true m1 has to be less than m2

C
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
GMAT Instructor
Posts: 15539
Joined: Tue May 25, 2010 12:04 pmFollowed by: 1906 members
Location: New York, NY
Thanked: 13060 times
GMAT Score:790

by GMATGuruNY » Sun Apr 15, 2012 8:51 am
priyank.hirani wrote:Lines n and p lie in the xy plane.Is the slope of line n less than the slpe of line p??

(1)Lines n and p intersect at (5,1)
(2)The y intercept of line n is greater than the y intercept of line p.
Neither statement alone is sufficient to determine the relationship between the slopes.

Statements 1 and 2 combined:
Let (0,n) = the y-intercept of line n.
Let (0,p) = the y-intercept of line p.

Since (5,1) is on each line:
The slope of line n = (n-1)/(0-5) = (n-1)/(-5).
The slope of line p = (p-1)/(0-5) = (p-1)/(-5).

Since statement 2 indicates that n>p:
n-1 > p-1
(n-1)/(-5) < (p-1)/(-5). (When we divide by a negative value, we flip the inequality.)
Thus, the slope of line n < the slope of line p.
SUFFICIENT.

The correct answer is C.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 3835
Joined: Fri Apr 02, 2010 10:00 pmFollowed by: 523 members
Location: Milpitas, CA
Thanked: 1854 times
GMAT Score:770

by Anurag@Gurome » Sun Apr 15, 2012 7:51 pm
priyank.hirani wrote:Lines n and p lie in the xy plane.Is the slope of line n less than the slpe of line p??

(1)Lines n and p intersect at (5,1)
(2)The y intercept of line n is greater than the y intercept of line p.
Let us assume that equation of line n is y = m1x + b1 and equations of line p is y = m2x + b2
Question is: Is m1 < m2?

(1) Lines n and p intersect at (5,1).
1 = m1 * 5 + b1 and 1 = m2 * 5 + b2
Subtracting the equations, we get, 0 = 5(m1 - m2) + (b1 - b2)
b2 - b1 = 5(m1 - m2); NOT sufficient.

(2) The y intercept of line n is greater than the y intercept of line p implies b1 > b2 or b2 - b1 < 0; NOT sufficient.

Combining (1) and (2), b2 - b1 = 5(m1 - m2) and (b2 - b1) < 0 implies 5(m1 - m2) < 0
m1 - m2 < 0
m1 < m2; SUFFICIENT.

The correct answer is C.
Anurag Mairal, Ph.D., MBA
GMAT Expert, Admissions and Career Guidance
Gurome, Inc.
1-800-566-4043 (USA)

Join Our Facebook Groups
GMAT with Gurome
https://www.facebook.com/groups/272466352793633/
Admissions with Gurome
https://www.facebook.com/groups/461459690536574/
Career Advising with Gurome
https://www.facebook.com/groups/360435787349781/
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1