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Problem Solving — algebra and arithmetic
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Senior | Next Rank: 100 Posts
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by AJWILL » Fri Jul 20, 2012 1:16 am
In compny x the median annual salary is $50000. what percent of the employees earned less than $80000 and more than $50,000?
1)the employees who earned less than $80,000 and more than $50,000 is equal to the number of the employees who earned no less than $80,000
2)30% of the total salary was earned by the employees who earned less than $80000 and more than $50000
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Source: — Quantitative Reasoning |
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by vinodsundaram » Fri Jul 20, 2012 5:17 am
I'm assuming Median Salary is the salary of the middle person while the total people are listed out.

consider $0-50K , $50-80K , >$80K ranges

Statement 1:
=> $50-80K = x (say).
Also >$80K = x

Whether the total number of people needed is irrelevant, as Median will have equal number of elements on either side.
Therefore , On the Right side of median= (2x) people.
=> On left (i.e $0-50K)= 2x people.

The required % of 50-80K is x/ (2x+2x) = x/4x = 25%
1 is sufficient.

Statement 2:
$50-80K = 30% of Total Salary. For sure >50K set has the bulk of the percentage in salary. Same cannot be said about the number of people. No calculation on the number can be made.
Hence 2 is insufficient.


IMO A
Hope i was on the right track.
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